What is the answer to (3x-4)(2x+1)+4=6x^2-5x ?

The answer to (3x-4)(2x+1)+4=6x^2-5x is True for all x

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(3x-4)(2x+1)+4=6x^2-5x

(3 x - 4) (2 x + 1) + 4 = 6 x^{2} - 5 x

True for all x

Solution steps

(3 x - 4) (2 x + 1) + 4 = 6 x^{2} - 5 x

Expand

(3 x - 4) (2 x + 1) + 4 : 6 x^{2} - 5 x

6 x^{2} - 5 x = 6 x^{2} - 5 x

Subtract

6 x^{2} - 5 x

from both sides

6 x^{2} - 5 x - (6 x^{2} - 5 x) = 6 x^{2} - 5 x - (6 x^{2} - 5 x)

Simplify

0 = 0

Both sides are equal

True for all x

3 (5 a + 2) = \frac{3 - 6 a}{2}

- 3 x + 5 = 8

11 - 2 x = 4 x - 1

- 5 y = - 10

3 x + 2 - x = 11 x + 9

What is the answer to (3x-4)(2x+1)+4=6x^2-5x ?
The answer to (3x-4)(2x+1)+4=6x^2-5x is True for all x
Solve for x: (3x-4)(2x+1)+4=6x^2-5x
The solution is True for all x