What is the answer to solvefor c,x^3=c(x^2-y^2) ?

The answer to solvefor c,x^3=c(x^2-y^2) is c=(x^3)/(x^2-y^2);\quad x^2-y^2\ne 0

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solvefor c,x^3=c(x^2-y^2)

solve for

c, x^{3} = c (x^{2} - y^{2})

c = \frac{x ^{3}}{x ^{2} - y ^{2}}; x^{2} - y^{2} \neq = 0

Solution steps

x^{3} = c (x^{2} - y^{2})

Switch sides

c (x^{2} - y^{2}) = x^{3}

Divide both sides by

x^{2} - y^{2}; x^{2} - y^{2} \neq = 0

c = \frac{x ^{3}}{x ^{2} - y ^{2}}; x^{2} - y^{2} \neq = 0

\frac{5}{2} x - 3 = 7 x - 3

x, 6 x + y = 3

2 (3 w + 8) = 70

f, y = - f - 1

8 x - 4 + 3 x = 7 x + 11 x + 14

What is the answer to solvefor c,x^3=c(x^2-y^2) ?
The answer to solvefor c,x^3=c(x^2-y^2) is c=(x^3)/(x^2-y^2);\quad x^2-y^2\ne 0