What are the solutions to the equation 4x^2+24=0 ?

The solutions to the equation 4x^2+24=0 are x=sqrt(6)i,x=-sqrt(6)i

Find the zeros of 4x^2+24=0

The zeros of 4x^2+24=0 are x=sqrt(6)i,x=-sqrt(6)i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4 x^{2} + 24 = 0

x = 6 i, x = - 6 i

Solution steps

4 x^{2} + 24 = 0

Move

24

to the right side

4 x^{2} = - 24

Divide both sides by

4

x^{2} = - 6

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 6, x = - - 6

- 6 = 6 i

- - 6 = - 6 i

x = 6 i, x = - 6 i

200 a^{6} b^{7}

\frac{( x ^{6} - 4 ^{6} )}{( x - 4 )}

- 7 q + 8 = - 8 + 3 q

- x^{2} - 2 = 0

a \frac{5}{4} b \frac{13}{4}

What are the solutions to the equation 4x^2+24=0 ?
The solutions to the equation 4x^2+24=0 are x=sqrt(6)i,x=-sqrt(6)i
Find the zeros of 4x^2+24=0
The zeros of 4x^2+24=0 are x=sqrt(6)i,x=-sqrt(6)i