What is the answer to 3(x+2)(2x-5)=(2x)(3x-2)-29 ?

The answer to 3(x+2)(2x-5)=(2x)(3x-2)-29 is x=1

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3(x+2)(2x-5)=(2x)(3x-2)-29

3 (x + 2) (2 x - 5) = (2 x) (3 x - 2) - 29

x = 1

Solution steps

3 (x + 2) (2 x - 5) = (2 x) (3 x - 2) - 29

3 (x + 2) (2 x - 5) = 2 x (3 x - 2) - 29

Expand

(x + 2) (2 x - 5) : 2 x^{2} - x - 10

3 (2 x^{2} - x - 10) = 2 x (3 x - 2) - 29

Expand

3 (2 x^{2} - x - 10) : 6 x^{2} - 3 x - 30

6 x^{2} - 3 x - 30 = 2 x (3 x - 2) - 29

Expand

2 x (3 x - 2) : 6 x^{2} - 4 x

6 x^{2} - 3 x - 30 = 6 x^{2} - 4 x - 29

Move

30

to the right side

6 x^{2} - 3 x = 6 x^{2} - 4 x + 1

Subtract

6 x^{2} - 4 x

from both sides

6 x^{2} - 3 x - (6 x^{2} - 4 x) = 6 x^{2} - 4 x + 1 - (6 x^{2} - 4 x)

Simplify

x = 1

2 \frac{1}{4} x + \frac{1}{2} x = 44

35 x = - 105

14 a + 13 a + 8 = 22

\frac{2}{2} = 2

x + 8 = 20

What is the answer to 3(x+2)(2x-5)=(2x)(3x-2)-29 ?
The answer to 3(x+2)(2x-5)=(2x)(3x-2)-29 is x=1
Solve for x: 3(x+2)(2x-5)=(2x)(3x-2)-29
The solution is x=1