What is the answer to 3x(x-5)-(x-3)(x+3)=2(x+5)^2 ?

The answer to 3x(x-5)-(x-3)(x+3)=2(x+5)^2 is x=-41/35

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3x(x-5)-(x-3)(x+3)=2(x+5)^2

3 x (x - 5) - (x - 3) (x + 3) = 2 (x + 5)^{2}

x = - \frac{41}{35}

Decimal Notation

x = - 1.17142 \dots

Solution steps

3 x (x - 5) - (x - 3) (x + 3) = 2 (x + 5)^{2}

Expand

3 x (x - 5) - (x - 3) (x + 3) : 2 x^{2} - 15 x + 9

Expand

2 (x + 5)^{2} : 2 x^{2} + 20 x + 50

2 x^{2} - 15 x + 9 = 2 x^{2} + 20 x + 50

Move

9

to the right side

2 x^{2} - 15 x = 2 x^{2} + 20 x + 41

Subtract

2 x^{2} + 20 x

from both sides

2 x^{2} - 15 x - (2 x^{2} + 20 x) = 2 x^{2} + 20 x + 41 - (2 x^{2} + 20 x)

Simplify

- 35 x = 41

Divide both sides by

- 35

x = - \frac{41}{35}

x = \frac{x}{2}

x, f = x y^{2}

\frac{2 ( m + 4 ) + 13}{5} = \frac{21 - ( 8 - 3 m )}{4}

x, 11 x + 7 y = 123

y, 2 x + y = 0

What is the answer to 3x(x-5)-(x-3)(x+3)=2(x+5)^2 ?
The answer to 3x(x-5)-(x-3)(x+3)=2(x+5)^2 is x=-41/35
Solve for x: 3x(x-5)-(x-3)(x+3)=2(x+5)^2
The solution is x=-41/35