What is the answer to 3x(2x+4)-5x=6x^2+2x-7 ?

The answer to 3x(2x+4)-5x=6x^2+2x-7 is x=-7/5

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3x(2x+4)-5x=6x^2+2x-7

3 x (2 x + 4) - 5 x = 6 x^{2} + 2 x - 7

x = - \frac{7}{5}

Decimal Notation

x = - 1.4

Solution steps

3 x (2 x + 4) - 5 x = 6 x^{2} + 2 x - 7

Expand

3 x (2 x + 4) : 6 x^{2} + 12 x

6 x^{2} + 12 x - 5 x = 6 x^{2} + 2 x - 7

Add similar elements:

12 x - 5 x = 7 x

6 x^{2} + 7 x = 6 x^{2} + 2 x - 7

Subtract

6 x^{2} + 2 x

from both sides

6 x^{2} + 7 x - (6 x^{2} + 2 x) = 6 x^{2} + 2 x - 7 - (6 x^{2} + 2 x)

Simplify

5 x = - 7

Divide both sides by

5

x = - \frac{7}{5}

6 x + 3 - 6 x = 3

8 x + 5 = - 19 - 4 x

f = (- 1)^{2}

10 x + 12 x + 2 = 0

3 (2 x - 5) + 2 (4 x + 7) = 5 (3 x + 1)

What is the answer to 3x(2x+4)-5x=6x^2+2x-7 ?
The answer to 3x(2x+4)-5x=6x^2+2x-7 is x=-7/5
Solve for x: 3x(2x+4)-5x=6x^2+2x-7
The solution is x=-7/5