What is the answer to solvefor x,v^2=u^2+2ax ?

The answer to solvefor x,v^2=u^2+2ax is x=(v^2-u^2)/(2a);\quad a\ne 0

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solvefor x,v^2=u^2+2ax

solve for

x, v^{2} = u^{2} + 2 a x

x = \frac{v ^{2} - u ^{2}}{2 a}; a \neq = 0

Solution steps

v^{2} = u^{2} + 2 a x

Switch sides

u^{2} + 2 a x = v^{2}

Move

u^{2}

to the right side

2 a x = v^{2} - u^{2}

Divide both sides by

2 a; a \neq = 0

x = \frac{v ^{2} - u ^{2}}{2 a}; a \neq = 0

7 x - 7 = - x + 1

y = 0 - 3

2 x - \frac{3 x}{4} = \frac{x}{10} - \frac{3}{5}

x, 7 x + 3 y = 12

y = 3 - 3

What is the answer to solvefor x,v^2=u^2+2ax ?
The answer to solvefor x,v^2=u^2+2ax is x=(v^2-u^2)/(2a);\quad a\ne 0