What are the solutions to the equation 5x^2-2x-24=0 ?

The solutions to the equation 5x^2-2x-24=0 are x= 12/5 ,x=-2

Find the zeros of 5x^2-2x-24=0

The zeros of 5x^2-2x-24=0 are x= 12/5 ,x=-2

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5 x^{2} - 2 x - 24 = 0

x = \frac{12}{5}, x = - 2

Decimal Notation

x = 2.4, x = - 2

Solution steps

5 x^{2} - 2 x - 24 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 5 ( - 24 )}{2 \cdot 5}

(- 2)^{2} - 4 \cdot 5 (- 24) = 22

x_{1, 2} = \frac{- ( - 2 ) \pm 22}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 22}{2 \cdot 5}, x_{2} = \frac{- ( - 2 ) - 22}{2 \cdot 5}

x = \frac{- ( - 2 ) + 22}{2 \cdot 5} : \frac{12}{5}

x = \frac{- ( - 2 ) - 22}{2 \cdot 5} : - 2

The solutions to the quadratic equation are:

x = \frac{12}{5}, x = - 2

x^{2} - 9 x + 4 x - 36

- 18 < 9 x

(3 x y z^{2}) (x^{2}) (\frac{1}{5} x^{2} y)

∣ 3 x - 1 ∣ + 3 \geq 9

\frac{\frac{π}{2}}{\frac{1}{2}}

What are the solutions to the equation 5x^2-2x-24=0 ?
The solutions to the equation 5x^2-2x-24=0 are x= 12/5 ,x=-2
Find the zeros of 5x^2-2x-24=0
The zeros of 5x^2-2x-24=0 are x= 12/5 ,x=-2