What is the answer to solvefor a,tag^2x-3=0 ?

The answer to solvefor a,tag^2x-3=0 is a= 3/(tg^2x);\quad tg^2x\ne 0

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Solution

solve for

a, t a g^{2} x - 3 = 0

a = \frac{3}{t g ^{2} x}; t g^{2} x \neq = 0

Solution steps

t a g^{2} x - 3 = 0

Move

3

to the right side

t a g^{2} x = 3

Divide both sides by

t g^{2} x; t g^{2} x \neq = 0

a = \frac{3}{t g ^{2} x}; t g^{2} x \neq = 0

f, f = {3 x + 5}

- 10 + y = 6

- 30 = 4 - 8 x

- 0.1 x + \frac{3}{10} = \frac{4}{10}

3 (2 u + 8) = 60

What is the answer to solvefor a,tag^2x-3=0 ?
The answer to solvefor a,tag^2x-3=0 is a= 3/(tg^2x);\quad tg^2x\ne 0