What is the answer to solvefor d,Hd+4Md=g^3 ?

The answer to solvefor d,Hd+4Md=g^3 is d=(g^3)/(H+4M);\quad H+4M\ne 0

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solvefor d,Hd+4Md=g^3

solve for

d, H d + 4 M d = g^{3}

d = \frac{g ^{3}}{H + 4 M}; H + 4 M \neq = 0

Solution steps

H d + 4 M d = g^{3}

Factor

H d + 4 M d : d (H + 4 M)

d (H + 4 M) = g^{3}

Divide both sides by

H + 4 M; H + 4 M \neq = 0

d = \frac{g ^{3}}{H + 4 M}; H + 4 M \neq = 0

x, 6 x - 3 y - 12 = 0

x, y + 2 x = - 1

- 6.74 = - 1.8 y + 0.1

x, 3 y - 5 x = 2

x = lo g_{2} (\frac{1}{16})

What is the answer to solvefor d,Hd+4Md=g^3 ?
The answer to solvefor d,Hd+4Md=g^3 is d=(g^3)/(H+4M);\quad H+4M\ne 0