What are the solutions to the equation (y+4)^2=4 ?

The solutions to the equation (y+4)^2=4 are y=-2,y=-6

Find the zeros of (y+4)^2=4

The zeros of (y+4)^2=4 are y=-2,y=-6

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(y + 4)^{2} = 4

y = - 2, y = - 6

Solution steps

(y + 4)^{2} = 4

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

y + 4 = 4 : y = - 2

Solve

y + 4 = - 4 : y = - 6

The solutions to the quadratic equation are:

y = - 2, y = - 6

2 x^{2} + 5 x + 5 = 0

(2 x + 1)^{2} + 7 (2 x + 1) + 12

4 + 3 (x + 2) = 10

- 16 t^{2} + 503 t + 6 = 0

7 x^{4} y (9 x^{4} y^{3})

What are the solutions to the equation (y+4)^2=4 ?
The solutions to the equation (y+4)^2=4 are y=-2,y=-6
Find the zeros of (y+4)^2=4
The zeros of (y+4)^2=4 are y=-2,y=-6