What is the answer to (b+1)(b+4)=b(b+3)-8 ?

The answer to (b+1)(b+4)=b(b+3)-8 is b=-6

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(b+1)(b+4)=b(b+3)-8

(b + 1) (b + 4) = b (b + 3) - 8

b = - 6

Solution steps

(b + 1) (b + 4) = b (b + 3) - 8

Expand

b (b + 3) : b^{2} + 3 b

b^{2} + 5 b + 4 = b^{2} + 3 b - 8

Expand

(b + 1) (b + 4) : b^{2} + 5 b + 4

b^{2} + 5 b + 4 = b^{2} + 3 b - 8

Move

4

to the right side

b^{2} + 5 b = b^{2} + 3 b - 12

Subtract

b^{2} + 3 b

from both sides

b^{2} + 5 b - (b^{2} + 3 b) = b^{2} + 3 b - 12 - (b^{2} + 3 b)

Simplify

2 b = - 12

Divide both sides by

2

b = - 6

x, 7 x - 6 y = 42

- 6 v - 20 - 17 v = 19 - 20 v

k, x^{2} + 6 x + k = 0

25 = \frac{30 x}{0.7 5 ^{2}}

10 + \frac{x}{3} = 4

What is the answer to (b+1)(b+4)=b(b+3)-8 ?
The answer to (b+1)(b+4)=b(b+3)-8 is b=-6
Solve for b: (b+1)(b+4)=b(b+3)-8
The solution is b=-6