What is the answer to solvefor d,u=a+(n-1)d ?

The answer to solvefor d,u=a+(n-1)d is d=(u-a)/(n-1);\quad n\ne 1

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solvefor d,u=a+(n-1)d

solve for

d, u = a + (n - 1) d

d = \frac{u - a}{n - 1}; n \neq = 1

Solution steps

u = a + (n - 1) d

Switch sides

a + (n - 1) d = u

Move

a

to the right side

(n - 1) d = u - a

Divide both sides by

n - 1; n \neq = 1

d = \frac{u - a}{n - 1}; n \neq = 1

x, 4 x + 3 y = 36

x, 4 x = 2 y

\frac{12 + x}{- 15} = - 3

s, x - sin (x) = 0

5 + [3 + (x - 1)] - 10 = 4 x - 12

What is the answer to solvefor d,u=a+(n-1)d ?
The answer to solvefor d,u=a+(n-1)d is d=(u-a)/(n-1);\quad n\ne 1