What is (2x^0y^2)^{-3}*2yx^3 ?

The solution to (2x^0y^2)^{-3}*2yx^3 is (x^3)/(4y^5)

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simplify (2x^0y^2)^{-3}*2yx^3

simplify

(2 x^{0} y^{2})^{- 3} \cdot 2 y x^{3}

\frac{x ^{3}}{4 y ^{5}}

Solution steps

(2 x^{0} y^{2})^{- 3} \cdot 2 y x^{3}

Simplify

(2 x^{0} y^{2})^{- 3} : \frac{1}{8 y ^{6}}

= \frac{1}{8 y ^{6}} \cdot 2 y x^{3}

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot 2 y x ^{3}}{8 y ^{6}}

Multiply the numbers:

1 \cdot 2 = 2

= \frac{2 y x ^{3}}{8 y ^{6}}

Factor the number:

8 = 2 \cdot 4

= \frac{2 y x ^{3}}{2 \cdot 4 y ^{6}}

Cancel the common factor:

2

= \frac{y x ^{3}}{4 y ^{6}}

Simplify

\frac{y}{y ^{6}} : \frac{1}{y ^{5}}

= \frac{x ^{3}}{4 y ^{5}}

3 x^{2} + 11 x - 4 < 0

2 (x - 2) = 10

x^{3} - x^{2} + 5 x + 7

- 8 \leq 10 - x \leq 1

What is (2x^0y^2)^{-3}*2yx^3 ?
The solution to (2x^0y^2)^{-3}*2yx^3 is (x^3)/(4y^5)