en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

1/5-2|x+1|<= 0

Solution

\frac{1}{5} - 2 ∣ x + 1 ∣ \leq 0

Solution

x \leq - \frac{11}{10} or x \geq - \frac{9}{10}

+2

Interval Notation

(- \infty, - \frac{11}{10}] \cup [- \frac{9}{10}, \infty)

Decimal

x \leq - 1.1 or x \geq - 0.9

Solution steps

\frac{1}{5} - 2 ∣ x + 1 ∣ \leq 0

Move

\frac{1}{5}

to the right side

- 2 ∣ x + 1 ∣ \leq - \frac{1}{5}

Multiply both sides by

- 1

2 ∣ x + 1 ∣ \geq \frac{1}{5}

Divide both sides by

2

∣ x + 1 ∣ \geq \frac{1}{10}

Apply absolute rule: If

∣ u ∣ \geq a, a > 0

then

u \leq - a

or

u \geq a

x + 1 \leq - \frac{1}{10} or x + 1 \geq \frac{1}{10}

x + 1 \leq - \frac{1}{10} or x + 1 \geq \frac{1}{10}

x \leq - \frac{11}{10} or x \geq - \frac{9}{10}

Graph

Popular Examples

∣ 3 y - 3 ∣ \geq - 7

2/3 y+1/2 (y-3)=(y+1)/6

\frac{2}{3} y + \frac{1}{2} (y - 3) = \frac{y + 1}{6}

simplify (1/5)^{-3}simplify

(\frac{1}{5})^{- 3}

-4(t-3)<= 40\lor 5+t<13

- 4 (t - 3) \leq 40 or 5 + t < 13

factor x^3-3x^2+3x-1 factor

x^{3} - 3 x^{2} + 3 x - 1

Frequently Asked Questions (FAQ)

What is 1/5-2|x+1|<= 0 ?
The solution to 1/5-2|x+1|<= 0 is x<=-11/10 \lor x>=-9/10