What are the solutions to the equation 6x^2+6x-120=0 ?

The solutions to the equation 6x^2+6x-120=0 are x=4,x=-5

Find the zeros of 6x^2+6x-120=0

The zeros of 6x^2+6x-120=0 are x=4,x=-5

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6 x^{2} + 6 x - 120 = 0

x = 4, x = - 5

Solution steps

6 x^{2} + 6 x - 120 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 6 ( - 120 )}{2 \cdot 6}

6^{2} - 4 \cdot 6 (- 120) = 54

x_{1, 2} = \frac{- 6 \pm 54}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 6 + 54}{2 \cdot 6}, x_{2} = \frac{- 6 - 54}{2 \cdot 6}

x = \frac{- 6 + 54}{2 \cdot 6} : 4

x = \frac{- 6 - 54}{2 \cdot 6} : - 5

The solutions to the quadratic equation are:

x = 4, x = - 5

\frac{m}{4} < 2

x \geq \frac{8}{x + 2}

- 3 (u + 5) + 5 u = 2 (u - 6)

3 (v - 14) = 9

f = \frac{( 3 ) - 2}{( 3 ) ^{2} - 4}

What are the solutions to the equation 6x^2+6x-120=0 ?
The solutions to the equation 6x^2+6x-120=0 are x=4,x=-5
Find the zeros of 6x^2+6x-120=0
The zeros of 6x^2+6x-120=0 are x=4,x=-5