What is the answer to ((x-1))/2 =((x-2))/3+((2x-3))/4 ?

The answer to ((x-1))/2 =((x-2))/3+((2x-3))/4 is x= 11/4

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((x-1))/2 =((x-2))/3+((2x-3))/4

\frac{( x - 1 )}{2} = \frac{( x - 2 )}{3} + \frac{( 2 x - 3 )}{4}

x = \frac{11}{4}

Decimal Notation

x = 2.75

Solution steps

\frac{( x - 1 )}{2} = \frac{( x - 2 )}{3} + \frac{( 2 x - 3 )}{4}

\frac{( x - 1 )}{2} = \frac{x - 2}{3} + \frac{2 x - 3}{4}

Multiply by LCM

6 (x - 1) = 4 (x - 2) + 3 (2 x - 3)

Expand

6 (x - 1) : 6 x - 6

Expand

4 (x - 2) + 3 (2 x - 3) : 10 x - 17

6 x - 6 = 10 x - 17

Move

6

to the right side

6 x = 10 x - 11

Move

10 x

to the left side

- 4 x = - 11

Divide both sides by

- 4

x = \frac{11}{4}

x, 12 x - 8 y = 24

1 - 2 (4 - 3 (x + 1)) = 4 (x - 5) - 1

- 60 = - 4 n - 20

x, 6 x - 7 y = 63

f = (- 1)^{2} + 1

What is the answer to ((x-1))/2 =((x-2))/3+((2x-3))/4 ?
The answer to ((x-1))/2 =((x-2))/3+((2x-3))/4 is x= 11/4
Solve for x: ((x-1))/2 =((x-2))/3+((2x-3))/4
The solution is x= 11/4