What is the answer to 3(2k-5)-k=4-(3k+7) ?

The answer to 3(2k-5)-k=4-(3k+7) is k= 3/2

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3(2k-5)-k=4-(3k+7)

3 (2 k - 5) - k = 4 - (3 k + 7)

k = \frac{3}{2}

Decimal Notation

k = 1.5

Solution steps

3 (2 k - 5) - k = 4 - (3 k + 7)

Expand

3 (2 k - 5) - k : 5 k - 15

Expand

4 - (3 k + 7) : - 3 k - 3

5 k - 15 = - 3 k - 3

Move

15

to the right side

5 k = - 3 k + 12

Move

3 k

to the left side

8 k = 12

Divide both sides by

8

k = \frac{3}{2}

0.12 + 3.76 r + 0.16 = 3.6 r - 0.2

a, an = 2 n

9 (\frac{x - 1}{3}) - 3 (\frac{x - 2}{2}) = 9

a, a + b = 6

x, 3 y + \frac{x}{2} - 4 = 8

What is the answer to 3(2k-5)-k=4-(3k+7) ?
The answer to 3(2k-5)-k=4-(3k+7) is k= 3/2
Solve for k: 3(2k-5)-k=4-(3k+7)
The solution is k= 3/2