What are the solutions to the equation 5x^2-7x=0 ?

The solutions to the equation 5x^2-7x=0 are x= 7/5 ,x=0

Find the zeros of 5x^2-7x=0

The zeros of 5x^2-7x=0 are x= 7/5 ,x=0

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5 x^{2} - 7 x = 0

x = \frac{7}{5}, x = 0

Decimal Notation

x = 1.4, x = 0

Solution steps

5 x^{2} - 7 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 5 \cdot 0}{2 \cdot 5}

(- 7)^{2} - 4 \cdot 5 \cdot 0 = 7

x_{1, 2} = \frac{- ( - 7 ) \pm 7}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 7}{2 \cdot 5}, x_{2} = \frac{- ( - 7 ) - 7}{2 \cdot 5}

x = \frac{- ( - 7 ) + 7}{2 \cdot 5} : \frac{7}{5}

x = \frac{- ( - 7 ) - 7}{2 \cdot 5} : 0

The solutions to the quadratic equation are:

x = \frac{7}{5}, x = 0

18 + 50

- 45 + 25 - 20 - 26

1024 - 16 t^{2} = 0

- 3 m = 25

x^{2} - 2 x - 3 \geq 0

What are the solutions to the equation 5x^2-7x=0 ?
The solutions to the equation 5x^2-7x=0 are x= 7/5 ,x=0
Find the zeros of 5x^2-7x=0
The zeros of 5x^2-7x=0 are x= 7/5 ,x=0