What is the answer to (3/2 y+2-3y)+(-3+4y-2/6 y)=12 ?

The answer to (3/2 y+2-3y)+(-3+4y-2/6 y)=12 is y=6

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(3/2 y+2-3y)+(-3+4y-2/6 y)=12

(\frac{3}{2} y + 2 - 3 y) + (- 3 + 4 y - \frac{2}{6} y) = 12

y = 6

Solution steps

(\frac{3}{2} y + 2 - 3 y) + (- 3 + 4 y - \frac{2}{6} y) = 12

Simplify

(\frac{3}{2} y + 2 - 3 y) + (- 3 + 4 y - \frac{2}{6} y) : \frac{3}{2} y + 4 y - \frac{y}{3} - 3 y - 1

\frac{3}{2} y + 4 y - \frac{y}{3} - 3 y - 1 = 12

Move

1

to the right side

\frac{3}{2} y + 4 y - \frac{y}{3} - 3 y = 13

Multiply by LCM

13 y = 78

Divide both sides by

13

y = 6

\frac{- x - 21}{3} = 6 x + 2

x, 6 x y - 6 y = 0

x, 2 x - 10 y = 20

x, y = 2 x + 4

x, 6 x y - 6 x = 0

What is the answer to (3/2 y+2-3y)+(-3+4y-2/6 y)=12 ?
The answer to (3/2 y+2-3y)+(-3+4y-2/6 y)=12 is y=6
Solve for y: (3/2 y+2-3y)+(-3+4y-2/6 y)=12
The solution is y=6