What are the solutions to the equation 12x^2+17x-7=0 ?

The solutions to the equation 12x^2+17x-7=0 are x= 1/3 ,x=-7/4

Find the zeros of 12x^2+17x-7=0

The zeros of 12x^2+17x-7=0 are x= 1/3 ,x=-7/4

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12 x^{2} + 17 x - 7 = 0

x = \frac{1}{3}, x = - \frac{7}{4}

Decimal Notation

x = 0.33333 \dots, x = - 1.75

Solution steps

12 x^{2} + 17 x - 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 17 \pm 1 7 ^{2} - 4 \cdot 12 ( - 7 )}{2 \cdot 12}

1 7^{2} - 4 \cdot 12 (- 7) = 25

x_{1, 2} = \frac{- 17 \pm 25}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- 17 + 25}{2 \cdot 12}, x_{2} = \frac{- 17 - 25}{2 \cdot 12}

x = \frac{- 17 + 25}{2 \cdot 12} : \frac{1}{3}

x = \frac{- 17 - 25}{2 \cdot 12} : - \frac{7}{4}

The solutions to the quadratic equation are:

x = \frac{1}{3}, x = - \frac{7}{4}

3 x - 9 = x + 7

8 x y^{2}

x^{2} + 5 x - 24 \geq 0

\frac{3}{7} x = 21

\frac{( x ^{\frac{1}{2}} s ^{\frac{2}{5}} ) ^{10}}{x ^{2}}

What are the solutions to the equation 12x^2+17x-7=0 ?
The solutions to the equation 12x^2+17x-7=0 are x= 1/3 ,x=-7/4
Find the zeros of 12x^2+17x-7=0
The zeros of 12x^2+17x-7=0 are x= 1/3 ,x=-7/4