What is the answer to solvefor B,A=Bsqrt(x^2+r^2) ?

The answer to solvefor B,A=Bsqrt(x^2+r^2) is B= A/(sqrt(x^2+r^2));\quad sqrt(x^2+r^2)\ne 0

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solvefor B,A=Bsqrt(x^2+r^2)

solve for

B, A = B x^{2} + r^{2}

B = \frac{A}{x ^{2} + r ^{2}}; x^{2} + r^{2} \neq = 0

Solution steps

A = B x^{2} + r^{2}

Switch sides

B x^{2} + r^{2} = A

Divide both sides by

x^{2} + r^{2}; x^{2} + r^{2} \neq = 0

B = \frac{A}{x ^{2} + r ^{2}}; x^{2} + r^{2} \neq = 0

5 (x - 3) - (x - 1) = (4 x + 2) - 1

7 = 2 x + 3

g, 2 x + 4 = xg

4 x + 22 = - 34

7 x - 4 = 31

What is the answer to solvefor B,A=Bsqrt(x^2+r^2) ?
The answer to solvefor B,A=Bsqrt(x^2+r^2) is B= A/(sqrt(x^2+r^2));\quad sqrt(x^2+r^2)\ne 0