What is the answer to z=(-sqrt(3)+i)/(-1-i) ?

The answer to z=(-sqrt(3)+i)/(-1-i) is z=(-1+sqrt(3))/2+i(-1-sqrt(3))/2

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z=(-sqrt(3)+i)/(-1-i)

z = \frac{- 3 + i}{- 1 - i}

z = \frac{- 1 + 3}{2} + i \frac{- 1 - 3}{2}

Solution steps

z = \frac{- 3 + i}{- 1 - i}

Simplify

\frac{- 3 + i}{- 1 - i} : \frac{- 1 + 3}{2} + i \frac{- 1 - 3}{2}

z = \frac{- 1 + 3}{2} + i \frac{- 1 - 3}{2}

x + 3 (x + 2) = 5 (x + 3) - 5

\frac{12}{5} (1)^{\frac{5}{3}} - 3 (1)^{\frac{2}{3}} + C = \frac{2}{5}

x, 2 x - 8 y = 22

lo g_{8} (1000) = lo g_{2} (10)

20 = - 2 k - 8

What is the answer to z=(-sqrt(3)+i)/(-1-i) ?
The answer to z=(-sqrt(3)+i)/(-1-i) is z=(-1+sqrt(3))/2+i(-1-sqrt(3))/2