What is the answer to -10/6 [ 2/7 x-1(2/7 x+3)]=-30/7+4x ?

The answer to -10/6 [ 2/7 x-1(2/7 x+3)]=-30/7+4x is x= 65/28

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-10/6 [ 2/7 x-1(2/7 x+3)]=-30/7+4x

- \frac{10}{6} [\frac{2}{7} x - 1 (\frac{2}{7} x + 3)] = - \frac{30}{7} + 4 x

x = \frac{65}{28}

Decimal Notation

x = 2.32142 \dots

Solution steps

- \frac{10}{6} [\frac{2}{7} x - 1 \cdot (\frac{2}{7} x + 3)] = - \frac{30}{7} + 4 x

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

- \frac{10 ( \frac{2}{7} x - 1 \cdot ( \frac{2}{7} x + 3 ) )}{6} = - \frac{30}{7} + 4 x

Multiply:

1 \cdot (\frac{2}{7} x + 3) = (\frac{2}{7} x + 3)

- \frac{10 ( \frac{2}{7} x - ( \frac{2}{7} x + 3 ) )}{6} = - \frac{30}{7} + 4 x

Cancel the common factor:

2

- \frac{5 ( \frac{2}{7} x - ( \frac{2}{7} x + 3 ) )}{3} = - \frac{30}{7} + 4 x

Multiply both sides by

3

- 5 (\frac{2}{7} x - (\frac{2}{7} x + 3)) = - \frac{90}{7} + 12 x

Expand

- 5 (\frac{2}{7} x - (\frac{2}{7} x + 3)) : 15

15 = - \frac{90}{7} + 12 x

Move

15

to the right side

0 = 12 x - \frac{195}{7}

Move

0

to the right side

= 12 x - \frac{195}{7}

Move

12 x

to the left side

- 12 x = - \frac{195}{7}

Divide both sides by

- 12

x = \frac{65}{28}

y, 8 x - 12 y = - 24

x + 10 = - 1

x + 2 (0) = 4

0 = - 3 x + 2

2 (x + 3) - 1 - x = \frac{1}{2} (5 x - 4 - 3 x)

What is the answer to -10/6 [ 2/7 x-1(2/7 x+3)]=-30/7+4x ?
The answer to -10/6 [ 2/7 x-1(2/7 x+3)]=-30/7+4x is x= 65/28
Solve for x: -10/6 [ 2/7 x-1(2/7 x+3)]=-30/7+4x
The solution is x= 65/28