What are the solutions to the equation r^2+2r=0 ?

The solutions to the equation r^2+2r=0 are r=0,r=-2

Find the zeros of r^2+2r=0

The zeros of r^2+2r=0 are r=0,r=-2

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r^{2} + 2 r = 0

r = 0, r = - 2

Solution steps

r^{2} + 2 r = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot 0 = 2

r_{1, 2} = \frac{- 2 \pm 2}{2 \cdot 1}

Separate the solutions

r_{1} = \frac{- 2 + 2}{2 \cdot 1}, r_{2} = \frac{- 2 - 2}{2 \cdot 1}

r = \frac{- 2 + 2}{2 \cdot 1} : 0

r = \frac{- 2 - 2}{2 \cdot 1} : - 2

The solutions to the quadratic equation are:

r = 0, r = - 2

\frac{1}{\frac{4}{9}}

60 \leq \frac{m}{3}

1985.256 = x (3.397 \cdot 1 0^{6} \cdot 2.2 + 3.397 \cdot 1 0^{6})

3 (1 x + 4) = 48

What are the solutions to the equation r^2+2r=0 ?
The solutions to the equation r^2+2r=0 are r=0,r=-2
Find the zeros of r^2+2r=0
The zeros of r^2+2r=0 are r=0,r=-2