What are the solutions to the equation solvefor b,f=b^2xc ?

The solutions to the equation solvefor b,f=b^2xc are b=sqrt(f/(xc)),b=-sqrt(f/(xc));\quad xc\ne 0

Find the zeros of solvefor b,f=b^2xc

The zeros of solvefor b,f=b^2xc are b=sqrt(f/(xc)),b=-sqrt(f/(xc));\quad xc\ne 0

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solve for

b, f = b^{2} x c

b = \frac{f}{x c}, b = - \frac{f}{x c}; x c \neq = 0

Solution steps

f = b^{2} x c

Switch sides

b^{2} x c = f

Divide both sides by

x c; x c \neq = 0

b^{2} = \frac{f}{x c}; x c \neq = 0

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

b = \frac{f}{x c}, b = - \frac{f}{x c}; x c \neq = 0

x, x + 2 y - \frac{1}{3} (3 x - 2) = - \frac{4}{3}

8 + 12 x = 15 x - 19

p, p + q = 7

(a + 5) (a + 3) = a^{2} + 2 a + 5

- 0.2 (5 x - 1) = x

What are the solutions to the equation solvefor b,f=b^2xc ?
The solutions to the equation solvefor b,f=b^2xc are b=sqrt(f/(xc)),b=-sqrt(f/(xc));\quad xc\ne 0
Find the zeros of solvefor b,f=b^2xc
The zeros of solvefor b,f=b^2xc are b=sqrt(f/(xc)),b=-sqrt(f/(xc));\quad xc\ne 0