What are the solutions to the equation 5v^2-v+8=0 ?

The solutions to the equation 5v^2-v+8=0 are v= 1/10+i(sqrt(159))/(10),v= 1/10-i(sqrt(159))/(10)

Find the zeros of 5v^2-v+8=0

The zeros of 5v^2-v+8=0 are v= 1/10+i(sqrt(159))/(10),v= 1/10-i(sqrt(159))/(10)

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5 v^{2} - v + 8 = 0

v = \frac{1}{10} + i \frac{159}{10}, v = \frac{1}{10} - i \frac{159}{10}

Solution steps

5 v^{2} - v + 8 = 0

Solve with the quadratic formula

v_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 5 \cdot 8}{2 \cdot 5}

Simplify

(- 1)^{2} - 4 \cdot 5 \cdot 8 : 159 i

v_{1, 2} = \frac{- ( - 1 ) \pm 159 i}{2 \cdot 5}

Separate the solutions

v_{1} = \frac{- ( - 1 ) + 159 i}{2 \cdot 5}, v_{2} = \frac{- ( - 1 ) - 159 i}{2 \cdot 5}

v = \frac{- ( - 1 ) + 159 i}{2 \cdot 5} : \frac{1}{10} + i \frac{159}{10}

v = \frac{- ( - 1 ) - 159 i}{2 \cdot 5} : \frac{1}{10} - i \frac{159}{10}

The solutions to the quadratic equation are:

v = \frac{1}{10} + i \frac{159}{10}, v = \frac{1}{10} - i \frac{159}{10}

1. 6^{2}

\frac{14 f ^{- 3} g ^{2} h ^{- 7}}{21 k ^{3}}

- 7 x \leq 21

n^{2} + 9 n + 8

- \frac{2}{3} \cdot 2

What are the solutions to the equation 5v^2-v+8=0 ?
The solutions to the equation 5v^2-v+8=0 are v= 1/10+i(sqrt(159))/(10),v= 1/10-i(sqrt(159))/(10)
Find the zeros of 5v^2-v+8=0
The zeros of 5v^2-v+8=0 are v= 1/10+i(sqrt(159))/(10),v= 1/10-i(sqrt(159))/(10)