What is the answer to solvefor h,A= 1/2 (b_{1}+b_{2})h ?

The answer to solvefor h,A= 1/2 (b_{1}+b_{2})h is h=(2A)/(b_{1)+b_{2}};\quad b_{1}+b_{2}\ne 0

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solvefor h,A= 1/2 (b_{1}+b_{2})h

solve for

h, A = \frac{1}{2} (b_{1} + b_{2}) h

h = \frac{2 A}{b _{1} + b _{2}}; b_{1} + b_{2} \neq = 0

Solution steps

A = \frac{1}{2} (b_{1} + b_{2}) h

Switch sides

\frac{1}{2} (b_{1} + b_{2}) h = A

Multiply both sides by

2

h (b_{1} + b_{2}) = 2 A

Divide both sides by

b_{1} + b_{2}; b_{1} + b_{2} \neq = 0

h = \frac{2 A}{b _{1} + b _{2}}; b_{1} + b_{2} \neq = 0

3 (2 x - 1) + 5 = 14

\frac{x}{8} = 10

x, 2 x + 3 y = 26

B, m^{3} = 4 (B - g)

- 50 x = - 50

What is the answer to solvefor h,A= 1/2 (b_{1}+b_{2})h ?
The answer to solvefor h,A= 1/2 (b_{1}+b_{2})h is h=(2A)/(b_{1)+b_{2}};\quad b_{1}+b_{2}\ne 0