What are the solutions to the equation r^2+2sqrt(6)r+6=0 ?

The solutions to the equation r^2+2sqrt(6)r+6=0 are r=-sqrt(6)

Find the zeros of r^2+2sqrt(6)r+6=0

The zeros of r^2+2sqrt(6)r+6=0 are r=-sqrt(6)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

r^{2} + 26 r + 6 = 0

r = - 6

Decimal Notation

r = - 2.44948 \dots

Solution steps

r^{2} + 26 r + 6 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- 2 6 \pm ( 2 6 ) ^{2} - 4 \cdot 1 \cdot 6}{2 \cdot 1}

(26)^{2} - 4 \cdot 1 \cdot 6 = 0

r_{1, 2} = \frac{- 2 6 \pm 0}{2 \cdot 1}

r = \frac{- 2 6}{2 \cdot 1}

\frac{- 2 6}{2 \cdot 1} = - 6

r = - 6

The solution to the quadratic equation is:

r = - 6

\frac{1}{2} x - 5 \leq \frac{3}{4} (x - 4) + \frac{( 4 x - 2 )}{3}

x^{2} - 23 x - 24

27 + 64 x^{3}

e^{- 2 l n (10)}

- \frac{5}{8} - (- \frac{1}{6})

What are the solutions to the equation r^2+2sqrt(6)r+6=0 ?
The solutions to the equation r^2+2sqrt(6)r+6=0 are r=-sqrt(6)
Find the zeros of r^2+2sqrt(6)r+6=0
The zeros of r^2+2sqrt(6)r+6=0 are r=-sqrt(6)