What is the answer to ln^2(2-3)+C=-1/2 ?

The answer to ln^2(2-3)+C=-1/2 is C=-1/2-ln^2(-1)

Solve for C: ln^2(2-3)+C=-1/2

The solution is C=-1/2-ln^2(-1)

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ln^{2} (2 - 3) + C = - \frac{1}{2}

C = - \frac{1}{2} - ln^{2} (- 1)

Solution steps

ln^{2} (2 - 3) + C = - \frac{1}{2}

Subtract the numbers:

2 - 3 = - 1

ln^{2} (- 1) + C = - \frac{1}{2}

Move

ln^{2} (- 1)

to the right side

C = - \frac{1}{2} - ln^{2} (- 1)

\frac{k}{6} + 8 = 5

24 x + 6 = 0

3 z - 4 = - 2 i z + 5 i

5 x = - 2

- 3 (2 x - 1) = - 21

What is the answer to ln^2(2-3)+C=-1/2 ?
The answer to ln^2(2-3)+C=-1/2 is C=-1/2-ln^2(-1)
Solve for C: ln^2(2-3)+C=-1/2
The solution is C=-1/2-ln^2(-1)