What are the solutions to the equation w^2-4=0 ?

The solutions to the equation w^2-4=0 are w=2,w=-2

Find the zeros of w^2-4=0

The zeros of w^2-4=0 are w=2,w=-2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

w^{2} - 4 = 0

w = 2, w = - 2

Solution steps

w^{2} - 4 = 0

Move

4

to the right side

w^{2} = 4

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

w = 4, w = - 4

4 = 2

- 4 = - 2

w = 2, w = - 2

\frac{4}{10} x - 4 x + \frac{6}{5} = \frac{4}{5}

15 n^{2} - 27 n - 6

\frac{x}{- \frac{1}{6}} = \frac{6}{7}

x m - 3 m y - 2 x y + 6 y^{2}

\frac{x ^{2} - 64}{x ^{2} - 16 x + 64}

What are the solutions to the equation w^2-4=0 ?
The solutions to the equation w^2-4=0 are w=2,w=-2
Find the zeros of w^2-4=0
The zeros of w^2-4=0 are w=2,w=-2