What are the solutions to the equation solvefor x,2x^2-3y^3=10 ?

The solutions to the equation solvefor x,2x^2-3y^3=10 are x=sqrt((10+3y^3)/2),x=-sqrt((10+3y^3)/2)

Find the zeros of solvefor x,2x^2-3y^3=10

The zeros of solvefor x,2x^2-3y^3=10 are x=sqrt((10+3y^3)/2),x=-sqrt((10+3y^3)/2)

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solve for

x, 2 x^{2} - 3 y^{3} = 10

x = \frac{10 + 3 y ^{3}}{2}, x = - \frac{10 + 3 y ^{3}}{2}

Solution steps

2 x^{2} - 3 y^{3} = 10

Move

3 y^{3}

to the right side

2 x^{2} = 10 + 3 y^{3}

Divide both sides by

2

x^{2} = \frac{10 + 3 y ^{3}}{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{10 + 3 y ^{3}}{2}, x = - \frac{10 + 3 y ^{3}}{2}

0.25 \cdot 10000 = x

3 - 2 x = 2 x - 5

- \frac{5}{2} (4 - f) = 3 + \frac{1}{3} (6 + f) - 2

x, a x + 3 x = b x + 5

x, 5 x - 3 y = 6

What are the solutions to the equation solvefor x,2x^2-3y^3=10 ?
The solutions to the equation solvefor x,2x^2-3y^3=10 are x=sqrt((10+3y^3)/2),x=-sqrt((10+3y^3)/2)
Find the zeros of solvefor x,2x^2-3y^3=10
The zeros of solvefor x,2x^2-3y^3=10 are x=sqrt((10+3y^3)/2),x=-sqrt((10+3y^3)/2)