What is the answer to log_{10}(3)(3x-2)=2 ?

The answer to log_{10}(3)(3x-2)=2 is x=(2+2log_{10}(3))/(3log_{10)(3)}

Solve for x: log_{10}(3)(3x-2)=2

The solution is x=(2+2log_{10}(3))/(3log_{10)(3)}

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lo g_{10} (3) (3 x - 2) = 2

x = \frac{2 + 2 lo g _{10} ( 3 )}{3 lo g _{10} ( 3 )}

Decimal Notation

x = 2.06393 \dots

Solution steps

lo g_{10} (3) (3 x - 2) = 2

Divide both sides by

lo g_{10} (3)

3 x - 2 = \frac{2}{lo g _{10} ( 3 )}

Move

2

to the right side

3 x = \frac{2}{lo g _{10} ( 3 )} + 2

Divide both sides by

3

x = \frac{2 + 2 lo g _{10} ( 3 )}{3 lo g _{10} ( 3 )}

X, X + Y = 10

2 x - 2 = 4 x - 6

x, k (3 x - 2) = 4 - 6 x

x, 6 x + 8 y = 48

\frac{3 x}{7} = 6

What is the answer to log_{10}(3)(3x-2)=2 ?
The answer to log_{10}(3)(3x-2)=2 is x=(2+2log_{10}(3))/(3log_{10)(3)}
Solve for x: log_{10}(3)(3x-2)=2
The solution is x=(2+2log_{10}(3))/(3log_{10)(3)}