What is the answer to (5y)/6-(y-3)/2 =(2y-1)/3-1/2 ?

The answer to (5y)/6-(y-3)/2 =(2y-1)/3-1/2 is y=7

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(5y)/6-(y-3)/2 =(2y-1)/3-1/2

\frac{5 y}{6} - \frac{y - 3}{2} = \frac{2 y - 1}{3} - \frac{1}{2}

y = 7

Solution steps

\frac{5 y}{6} - \frac{y - 3}{2} = \frac{2 y - 1}{3} - \frac{1}{2}

Multiply by LCM

5 y - 3 (y - 3) = 2 (2 y - 1) - 3

Expand

- 3 (y - 3) : - 3 y + 9

5 y - 3 y + 9 = 2 (2 y - 1) - 3

Add similar elements:

5 y - 3 y = 2 y

2 y + 9 = 2 (2 y - 1) - 3

Expand

2 (2 y - 1) - 3 : 4 y - 5

2 y + 9 = 4 y - 5

Move

9

to the right side

2 y = 4 y - 14

Move

4 y

to the left side

- 2 y = - 14

Divide both sides by

- 2

y = 7

y, 6 x + 5 y = - 15

b, h = f b

7 (2 x - 3) + 3 = 24

\frac{x}{12} = \frac{6}{10}

186 + 10 x = 25.5 x

What is the answer to (5y)/6-(y-3)/2 =(2y-1)/3-1/2 ?
The answer to (5y)/6-(y-3)/2 =(2y-1)/3-1/2 is y=7
Solve for y: (5y)/6-(y-3)/2 =(2y-1)/3-1/2
The solution is y=7