What is the answer to x^2+7x+10=(x+2)(x+5) ?

The answer to x^2+7x+10=(x+2)(x+5) is True for all x

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x^2+7x+10=(x+2)(x+5)

x^{2} + 7 x + 10 = (x + 2) (x + 5)

True for all x

Solution steps

x^{2} + 7 x + 10 = (x + 2) (x + 5)

Expand

(x + 2) (x + 5) : x^{2} + 7 x + 10

x^{2} + 7 x + 10 = x^{2} + 7 x + 10

Move

10

to the right side

x^{2} + 7 x = x^{2} + 7 x

Subtract

x^{2} + 7 x

from both sides

x^{2} + 7 x - (x^{2} + 7 x) = x^{2} + 7 x - (x^{2} + 7 x)

Simplify

0 = 0

Both sides are equal

True for all x

y, 3 x - y = - 2 y

5 x - 3 (4 x - 8) = - 11

4 (x + 5) = 3 (x - 2)

y = 4^{1}

2 (12 x + 3) - 3 (1 - 3 x) = 6 (x - 10)

What is the answer to x^2+7x+10=(x+2)(x+5) ?
The answer to x^2+7x+10=(x+2)(x+5) is True for all x
Solve for x: x^2+7x+10=(x+2)(x+5)
The solution is True for all x