What is the answer to (b+7)(b-6)=(b+2)(b-9) ?

The answer to (b+7)(b-6)=(b+2)(b-9) is b=3

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(b+7)(b-6)=(b+2)(b-9)

(b + 7) (b - 6) = (b + 2) (b - 9)

b = 3

Solution steps

(b + 7) (b - 6) = (b + 2) (b - 9)

Expand

(b + 7) (b - 6) : b^{2} + b - 42

Expand

(b + 2) (b - 9) : b^{2} - 7 b - 18

b^{2} + b - 42 = b^{2} - 7 b - 18

Move

42

to the right side

b^{2} + b = b^{2} - 7 b + 24

Subtract

b^{2} - 7 b

from both sides

b^{2} + b - (b^{2} - 7 b) = b^{2} - 7 b + 24 - (b^{2} - 7 b)

Simplify

8 b = 24

Divide both sides by

8

b = 3

lo g_{2} (65) = 6

\frac{5}{2}

- 17 b = - 21

b c^{2} - 4 b + 3 c^{2} - 12

e^{a} - e^{- a}

What is the answer to (b+7)(b-6)=(b+2)(b-9) ?
The answer to (b+7)(b-6)=(b+2)(b-9) is b=3
Solve for b: (b+7)(b-6)=(b+2)(b-9)
The solution is b=3