What is the answer to 2m+7^2-\sqrt[3]{27}+3m=-6+2^5 ?

The answer to 2m+7^2-\sqrt[3]{27}+3m=-6+2^5 is m=-4

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2m+7^2-\sqrt[3]{27}+3m=-6+2^5

m = - 4

Solution steps

Simplify

- 6 + 2^{5} : 26

5 m + 46 = 26

Move

46

to the right side

5 m = - 20

Divide both sides by

5

m = - 4

5 (x + 2) = 40

(9 a - 4) - (8 a + 2) = - 7

x + 15 = 8

X, 2 X Y = 2 Y^{2} - 3 X^{2}

x + 1 = 12

What is the answer to 2m+7^2-\sqrt[3]{27}+3m=-6+2^5 ?
The answer to 2m+7^2-\sqrt[3]{27}+3m=-6+2^5 is m=-4
Solve for m: 2m+7^2-\sqrt[3]{27}+3m=-6+2^5
The solution is m=-4