What are the solutions to the equation 9x^2+2x-1=0 ?

The solutions to the equation 9x^2+2x-1=0 are x=(-1+sqrt(10))/9 ,x=-(1+sqrt(10))/9

Find the zeros of 9x^2+2x-1=0

The zeros of 9x^2+2x-1=0 are x=(-1+sqrt(10))/9 ,x=-(1+sqrt(10))/9

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9 x^{2} + 2 x - 1 = 0

x = \frac{- 1 + 10}{9}, x = - \frac{1 + 10}{9}

Decimal Notation

x = 0.24025 \dots, x = - 0.46247 \dots

Solution steps

9 x^{2} + 2 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 9 ( - 1 )}{2 \cdot 9}

2^{2} - 4 \cdot 9 (- 1) = 210

x_{1, 2} = \frac{- 2 \pm 2 10}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- 2 + 2 10}{2 \cdot 9}, x_{2} = \frac{- 2 - 2 10}{2 \cdot 9}

x = \frac{- 2 + 2 10}{2 \cdot 9} : \frac{- 1 + 10}{9}

x = \frac{- 2 - 2 10}{2 \cdot 9} : - \frac{1 + 10}{9}

The solutions to the quadratic equation are:

x = \frac{- 1 + 10}{9}, x = - \frac{1 + 10}{9}

5 x^{2} - 19 x + 12

\frac{5 ( m ^{- 2} ) ^{3}}{20 m ^{9}}

∣ 2 x + 5 ∣ > 3

2 x^{3} + 3 x^{2} - 1 > 0

5 \cdot 70

What are the solutions to the equation 9x^2+2x-1=0 ?
The solutions to the equation 9x^2+2x-1=0 are x=(-1+sqrt(10))/9 ,x=-(1+sqrt(10))/9
Find the zeros of 9x^2+2x-1=0
The zeros of 9x^2+2x-1=0 are x=(-1+sqrt(10))/9 ,x=-(1+sqrt(10))/9