What is the answer to solvefor t,log_{1+(7.17)/(12)}(2)=12t ?

The answer to solvefor t,log_{1+(7.17)/(12)}(2)=12t is t=(log_{\frac{19.17)/(12)}(2)}{12}

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solvefor t,log_{1+(7.17)/(12)}(2)=12t

solve for

t, lo g_{1 + \frac{7.17}{12}} (2) = 12 t

t = \frac{lo g _{\frac{19.17}{12}} ( 2 )}{12}

Decimal Notation

t = 0.12330 \dots

Solution steps

lo g_{1 + \frac{7.17}{12}} (2) = 12 t

Switch sides

12 t = lo g_{1 + \frac{7.17}{12}} (2)

Join

1 + \frac{7.17}{12} : \frac{19.17}{12}

12 t = lo g_{\frac{19.17}{12}} (2)

Divide both sides by

12

t = \frac{lo g _{\frac{19.17}{12}} ( 2 )}{12}

z^{2} + 2 = (z - 1) (z + 1) + z

x, - 3 x - 2 y = 30

x, x - 2 y + 3 z = 9

3 (6 - 4 x) = - 2 (6 x - 9)

a^{1} = 1

What is the answer to solvefor t,log_{1+(7.17)/(12)}(2)=12t ?
The answer to solvefor t,log_{1+(7.17)/(12)}(2)=12t is t=(log_{\frac{19.17)/(12)}(2)}{12}