What are the solutions to the equation 4a^2-16a=-15 ?

The solutions to the equation 4a^2-16a=-15 are a= 5/2 ,a= 3/2

Find the zeros of 4a^2-16a=-15

The zeros of 4a^2-16a=-15 are a= 5/2 ,a= 3/2

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4 a^{2} - 16 a = - 15

a = \frac{5}{2}, a = \frac{3}{2}

Decimal Notation

a = 2.5, a = 1.5

Solution steps

4 a^{2} - 16 a = - 15

Move

15

to the left side

4 a^{2} - 16 a + 15 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 \cdot 4 \cdot 15}{2 \cdot 4}

(- 16)^{2} - 4 \cdot 4 \cdot 15 = 4

a_{1, 2} = \frac{- ( - 16 ) \pm 4}{2 \cdot 4}

Separate the solutions

a_{1} = \frac{- ( - 16 ) + 4}{2 \cdot 4}, a_{2} = \frac{- ( - 16 ) - 4}{2 \cdot 4}

a = \frac{- ( - 16 ) + 4}{2 \cdot 4} : \frac{5}{2}

a = \frac{- ( - 16 ) - 4}{2 \cdot 4} : \frac{3}{2}

The solutions to the quadratic equation are:

a = \frac{5}{2}, a = \frac{3}{2}

\frac{5}{3} + 1

3 x^{2} - 21 = 0

x^{4} + 15 x^{2} - 16

What are the solutions to the equation 4a^2-16a=-15 ?
The solutions to the equation 4a^2-16a=-15 are a= 5/2 ,a= 3/2
Find the zeros of 4a^2-16a=-15
The zeros of 4a^2-16a=-15 are a= 5/2 ,a= 3/2