What is the answer to solvefor z,x= 2/3 y+2z ?

The answer to solvefor z,x= 2/3 y+2z is z=(3x-2y)/6

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solvefor z,x= 2/3 y+2z

solve for

z, x = \frac{2}{3} y + 2 z

z = \frac{3 x - 2 y}{6}

Solution steps

x = \frac{2}{3} y + 2 z

Switch sides

\frac{2}{3} y + 2 z = x

Move

\frac{2}{3} y

to the right side

2 z = x - \frac{2}{3} y

Divide both sides by

2

z = \frac{3 x - 2 y}{6}

x, 3 x - \frac{1}{2} y = 9

2 y - 3 y = 5

\frac{3 + ( n + 1 ) i}{2 + 5 i} = z

x, 2 y + 3 x = - 6

y = 5 (0) + 3

What is the answer to solvefor z,x= 2/3 y+2z ?
The answer to solvefor z,x= 2/3 y+2z is z=(3x-2y)/6