What are the solutions to the equation -3u=u^2 ?

The solutions to the equation -3u=u^2 are u=0,u=-3

Find the zeros of -3u=u^2

The zeros of -3u=u^2 are u=0,u=-3

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- 3 u = u^{2}

u = 0, u = - 3

Solution steps

- 3 u = u^{2}

Switch sides

u^{2} = - 3 u

Move

3 u

to the left side

u^{2} + 3 u = 0

Solve with the quadratic formula

u_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

3^{2} - 4 \cdot 1 \cdot 0 = 3

u_{1, 2} = \frac{- 3 \pm 3}{2 \cdot 1}

Separate the solutions

u_{1} = \frac{- 3 + 3}{2 \cdot 1}, u_{2} = \frac{- 3 - 3}{2 \cdot 1}

u = \frac{- 3 + 3}{2 \cdot 1} : 0

u = \frac{- 3 - 3}{2 \cdot 1} : - 3

The solutions to the quadratic equation are:

u = 0, u = - 3

\frac{24 !}{3 ! ( 24 - 3 ) !}

\frac{7 x - 9}{x + 2} \leq 0

5 rs + 25 r - 3 s - 15

∣ 2 x + 1 ∣ + ∣ 4 - 3 x ∣ > 18

2 (7 v + 6) \leq 14 v + 13

What are the solutions to the equation -3u=u^2 ?
The solutions to the equation -3u=u^2 are u=0,u=-3
Find the zeros of -3u=u^2
The zeros of -3u=u^2 are u=0,u=-3