What are the solutions to the equation 3x^2-9x=x-5 ?

The solutions to the equation 3x^2-9x=x-5 are x=(5+sqrt(10))/3 ,x=(5-sqrt(10))/3

Find the zeros of 3x^2-9x=x-5

The zeros of 3x^2-9x=x-5 are x=(5+sqrt(10))/3 ,x=(5-sqrt(10))/3

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3 x^{2} - 9 x = x - 5

x = \frac{5 + 10}{3}, x = \frac{5 - 10}{3}

Decimal Notation

x = 2.72075 \dots, x = 0.61257 \dots

Solution steps

3 x^{2} - 9 x = x - 5

Move

5

to the left side

3 x^{2} - 9 x + 5 = x

Move

x

to the left side

3 x^{2} - 10 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 3 \cdot 5}{2 \cdot 3}

(- 10)^{2} - 4 \cdot 3 \cdot 5 = 210

x_{1, 2} = \frac{- ( - 10 ) \pm 2 10}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 10 ) + 2 10}{2 \cdot 3}, x_{2} = \frac{- ( - 10 ) - 2 10}{2 \cdot 3}

x = \frac{- ( - 10 ) + 2 10}{2 \cdot 3} : \frac{5 + 10}{3}

x = \frac{- ( - 10 ) - 2 10}{2 \cdot 3} : \frac{5 - 10}{3}

The solutions to the quadratic equation are:

x = \frac{5 + 10}{3}, x = \frac{5 - 10}{3}

- 7 = - 1 + \frac{x}{3}

8 p^{3} - 32 p^{2} + 28 p - 112

p^{2} + 10 p = 0

(\frac{4 x}{y ^{3}})^{- 2}

x^{2} + 8 + 16

What are the solutions to the equation 3x^2-9x=x-5 ?
The solutions to the equation 3x^2-9x=x-5 are x=(5+sqrt(10))/3 ,x=(5-sqrt(10))/3
Find the zeros of 3x^2-9x=x-5
The zeros of 3x^2-9x=x-5 are x=(5+sqrt(10))/3 ,x=(5-sqrt(10))/3