What is the answer to f=3(2/9)^3-8(2/9)^2+5(2/9)-30 ?

The answer to f=3(2/9)^3-8(2/9)^2+5(2/9)-30 is f=-7108/243

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f=3(2/9)^3-8(2/9)^2+5(2/9)-30

f = 3 (\frac{2}{9})^{3} - 8 (\frac{2}{9})^{2} + 5 (\frac{2}{9}) - 30

f = - \frac{7108}{243}

Decimal Notation

f = - 29.25102 \dots

Solution steps

f = 3 (\frac{2}{9})^{3} - 8 (\frac{2}{9})^{2} + 5 (\frac{2}{9}) - 30

Simplify

3 (\frac{2}{9})^{3} - 8 (\frac{2}{9})^{2} + 5 (\frac{2}{9}) - 30 : - \frac{7108}{243}

f = - \frac{7108}{243}

3 x - 4 = x + 6

- 8 = 4 (x - 1)

x, 2 y = 3 x - 1

x, 2 y = 3 x + 6

- 7 (- 3 x - 7) = 42 x + 49

What is the answer to f=3(2/9)^3-8(2/9)^2+5(2/9)-30 ?
The answer to f=3(2/9)^3-8(2/9)^2+5(2/9)-30 is f=-7108/243
Solve for f: f=3(2/9)^3-8(2/9)^2+5(2/9)-30
The solution is f=-7108/243