What is the answer to 6((x+1)/8-(2x-3}{16})=3(\frac{3x)/4-1/4)-3/8 (3x-2) ?

The answer to 6((x+1)/8-(2x-3}{16})=3(\frac{3x)/4-1/4)-3/8 (3x-2) is x= 5/3

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6((x+1)/8-(2x-3}{16})=3(\frac{3x)/4-1/4)-3/8 (3x-2)

6 (\frac{x + 1}{8} - \frac{2 x - 3}{16}) = 3 (\frac{3 x}{4} - \frac{1}{4}) - \frac{3}{8} (3 x - 2)

x = \frac{5}{3}

Decimal Notation

x = 1.66666 \dots

Solution steps

6 (\frac{x + 1}{8} - \frac{2 x - 3}{16}) = 3 (\frac{3 x}{4} - \frac{1}{4}) - \frac{3}{8} (3 x - 2)

Expand

6 (\frac{x + 1}{8} - \frac{2 x - 3}{16}) : \frac{15}{8}

Expand

3 (\frac{3 x}{4} - \frac{1}{4}) - \frac{3}{8} (3 x - 2) : \frac{9 x}{8}

\frac{15}{8} = \frac{9 x}{8}

Multiply both sides by

8

15 = 9 x

Move

15

to the right side

0 = 9 x - 15

Move

0

to the right side

= 9 x - 15

Move

9 x

to the left side

- 9 x = - 15

Divide both sides by

- 9

x = \frac{5}{3}

x, f = \frac{f ( x + h ) - f}{h}

45 + 21 x - 19 = 8 x + 2 + 12 x

\frac{x + 2}{3} + \frac{3 x - 1}{4} = \frac{x + 1}{2} + 4

r, r (t) = t^{2} i + t j

x, 15 x + 3 y = 1

What is the answer to 6((x+1)/8-(2x-3}{16})=3(\frac{3x)/4-1/4)-3/8 (3x-2) ?
The answer to 6((x+1)/8-(2x-3}{16})=3(\frac{3x)/4-1/4)-3/8 (3x-2) is x= 5/3
Solve for x: 6((x+1)/8-(2x-3}{16})=3(\frac{3x)/4-1/4)-3/8 (3x-2)
The solution is x= 5/3