What is the answer to solvefor a,y=ax^4-bx^2 ?

The answer to solvefor a,y=ax^4-bx^2 is a=(y+bx^2)/(x^4);\quad x\ne 0

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solvefor a,y=ax^4-bx^2

solve for

a, y = a x^{4} - b x^{2}

a = \frac{y + b x ^{2}}{x ^{4}}; x \neq = 0

Solution steps

y = a x^{4} - b x^{2}

Switch sides

a x^{4} - b x^{2} = y

Move

b x^{2}

to the right side

a x^{4} = y + b x^{2}

Divide both sides by

x^{4}; x \neq = 0

a = \frac{y + b x ^{2}}{x ^{4}}; x \neq = 0

8 ab c x - ab = 8 ab x + 1

0.3 z = 2 (z - 8.5)

lo g_{10} (3) (x) = 4

2 x + x = 36

\frac{1}{6} = \frac{5}{6} x - \frac{2}{3}

What is the answer to solvefor a,y=ax^4-bx^2 ?
The answer to solvefor a,y=ax^4-bx^2 is a=(y+bx^2)/(x^4);\quad x\ne 0