What is the answer to (x-3)(x^2+3x+9)-x(x^2-4)=1 ?

The answer to (x-3)(x^2+3x+9)-x(x^2-4)=1 is x=7

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(x-3)(x^2+3x+9)-x(x^2-4)=1

(x - 3) (x^{2} + 3 x + 9) - x (x^{2} - 4) = 1

x = 7

Solution steps

(x - 3) (x^{2} + 3 x + 9) - x (x^{2} - 4) = 1

Expand

(x - 3) (x^{2} + 3 x + 9) - x (x^{2} - 4) : 4 x - 27

4 x - 27 = 1

Move

27

to the right side

4 x = 28

Divide both sides by

4

x = 7

- 8 (2 x - 9) = 20 - 12 x

\frac{3 x}{4} = \frac{4 x - 3}{5}

7 x + 19 = 11 x - 89

- 3 y = 6

2 x + \frac{π}{2} = 0

What is the answer to (x-3)(x^2+3x+9)-x(x^2-4)=1 ?
The answer to (x-3)(x^2+3x+9)-x(x^2-4)=1 is x=7
Solve for x: (x-3)(x^2+3x+9)-x(x^2-4)=1
The solution is x=7