What is the answer to -2y-3-(-4y+5+(-y+2-(3y-1)+2y-5))=-(y-4) ?

The answer to -2y-3-(-4y+5+(-y+2-(3y-1)+2y-5))=-(y-4) is y=2

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-2y-3-(-4y+5+(-y+2-(3y-1)+2y-5))=-(y-4)

- 2 y - 3 - (- 4 y + 5 + (- y + 2 - (3 y - 1) + 2 y - 5)) = - (y - 4)

y = 2

Solution steps

- 2 y - 3 - (- 4 y + 5 + (- y + 2 - (3 y - 1) + 2 y - 5)) = - (y - 4)

Remove parentheses:

(- a) = - a

- 2 y - 3 - (- 4 y + 5 - y + 2 - (3 y - 1) + 2 y - 5) = - (y - 4)

Simplify

- 4 y + 5 - y + 2 - (3 y - 1) + 2 y - 5 : - 3 y - (3 y - 1) + 5 + 2 - 5

- 2 y - 3 - (- 3 y - (3 y - 1) + 5 + 2 - 5) = - (y - 4)

Expand

- 2 y - 3 - (- 3 y - (3 y - 1) + 5 + 2 - 5) : 4 y - 6

Expand

- (y - 4) : - y + 4

4 y - 6 = - y + 4

Move

6

to the right side

4 y = - y + 10

Move

y

to the left side

5 y = 10

Divide both sides by

5

y = 2

\frac{- 15 t + 15}{14} = 0

y = - 2^{2} + 3

x, 3 x + y - 10 = 0

3 x + 101 - 4 x - 33 = 108 - 16 x - 10

x + 13 = 31

What is the answer to -2y-3-(-4y+5+(-y+2-(3y-1)+2y-5))=-(y-4) ?
The answer to -2y-3-(-4y+5+(-y+2-(3y-1)+2y-5))=-(y-4) is y=2
Solve for y: -2y-3-(-4y+5+(-y+2-(3y-1)+2y-5))=-(y-4)
The solution is y=2