What is factor 21x^2+41x+10 ?

The solution to factor 21x^2+41x+10 is (7x+2)(3x+5)

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factor 21x^2+41x+10

factor

21 x^{2} + 41 x + 10

(7 x + 2) (3 x + 5)

Solution steps

21 x^{2} + 41 x + 10

Break the expression into groups

= (21 x^{2} + 6 x) + (35 x + 10)

Factor out

3 x

from

21 x^{2} + 6 x : 3 x (7 x + 2)

Factor out

5

from

35 x + 10 : 5 (7 x + 2)

= 3 x (7 x + 2) + 5 (7 x + 2)

Factor out common term

7 x + 2

= (7 x + 2) (3 x + 5)

\frac{( 1 + 2 i )}{( 3 - 4 i )}

\frac{\frac{2}{3}}{\frac{1}{2}}

\frac{x ^{- 4}}{x ^{- 6}}

3 w^{2} + w - 1 = 0

1 + (- \frac{2}{3}) - (- \frac{9}{2})

What is factor 21x^2+41x+10 ?
The solution to factor 21x^2+41x+10 is (7x+2)(3x+5)