What is the answer to ((x-2))/2+x=((x+1))/3-((x+3))/4 ?

The answer to ((x-2))/2+x=((x+1))/3-((x+3))/4 is x= 7/17

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((x-2))/2+x=((x+1))/3-((x+3))/4

\frac{( x - 2 )}{2} + x = \frac{( x + 1 )}{3} - \frac{( x + 3 )}{4}

x = \frac{7}{17}

Solution steps

\frac{( x - 2 )}{2} + x = \frac{( x + 1 )}{3} - \frac{( x + 3 )}{4}

\frac{x - 2}{2} + x = \frac{x + 1}{3} - \frac{x + 3}{4}

Multiply by LCM

6 (x - 2) + 12 x = 4 (x + 1) - 3 (x + 3)

Expand

6 (x - 2) + 12 x : 18 x - 12

Expand

4 (x + 1) - 3 (x + 3) : x - 5

18 x - 12 = x - 5

Move

12

to the right side

18 x = x + 7

Move

x

to the left side

17 x = 7

Divide both sides by

17

x = \frac{7}{17}

- 2 x - 4 = - 1 (- 2 x - 4)

0.5 (p + 3) = 3 (0.1 + 0.16 p)

- 43 = \frac{x}{5} - 475 x - 47

x, 7 x + 2 y = 2

5 (2 - x) + 3 (x + 6) = 10 - 4 (6 + 2 x)

What is the answer to ((x-2))/2+x=((x+1))/3-((x+3))/4 ?
The answer to ((x-2))/2+x=((x+1))/3-((x+3))/4 is x= 7/17
Solve for x: ((x-2))/2+x=((x+1))/3-((x+3))/4
The solution is x= 7/17